b^2-5b-150=0

Solution for b^2-5b-150=0 equation:

Simplifying
b2 + -5b + -150 = 0

Reorder the terms:
-150 + -5b + b2 = 0

Solving
-150 + -5b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-10 + -1b)(15 + -1b) = 0

Subproblem 1
Set the factor '(-10 + -1b)' equal to zero and attempt to solve:

Simplifying
-10 + -1b = 0

Solving
-10 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1b = 0 + 10
-1b = 0 + 10

Combine like terms: 0 + 10 = 10
-1b = 10

Divide each side by '-1'.
b = -10

Simplifying
b = -10
Subproblem 2
Set the factor '(15 + -1b)' equal to zero and attempt to solve:

Simplifying
15 + -1b = 0

Solving
15 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + -1b = 0 + -15

Combine like terms: 15 + -15 = 0
0 + -1b = 0 + -15
-1b = 0 + -15

Combine like terms: 0 + -15 = -15
-1b = -15

Divide each side by '-1'.
b = 15

Simplifying
b = 15
Solution
b = {-10, 15}